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8n^2+64n+96=0
a = 8; b = 64; c = +96;
Δ = b2-4ac
Δ = 642-4·8·96
Δ = 1024
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1024}=32$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(64)-32}{2*8}=\frac{-96}{16} =-6 $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(64)+32}{2*8}=\frac{-32}{16} =-2 $
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